document.write( "Question 356576: In testing a hybrid engine, engineers are trying various mixtures of gasoline and methanol. How much of a 90% gasoline mixture and a 75% gasoline mixture would be needed for 600 L of an 85% gasoline mixture?
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Algebra.Com's Answer #254620 by Fombitz(32388) $\"\"$ $\"About$

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Let A be the amount of 90% mixture, B the amount of 75% mixture.
\n" ); document.write( "Volume:
\n" ); document.write( "1. $\"A%2BB=600\"$
\n" ); document.write( "Concentration:
\n" ); document.write( " $\"90A%2B75B=85%28600%29\"$
\n" ); document.write( "2. $\"18A%2B15B=10200\"$
\n" ); document.write( "Multiply eq. 1 by (-15) and add to eq. 2 to eliminate B and solve for A.
\n" ); document.write( " $\"-15A-15B%2B18A%2B15B=-9000%2B10200\"$
\n" ); document.write( " $\"3A=1200\"$
\n" ); document.write( " $\"highlight%28A=400%29\"$ ml
\n" ); document.write( "Then from eq. 1,
\n" ); document.write( " $\"400%2BB=600\"$
\n" ); document.write( " $\"highlight%28B=200%29\"$ ml \n" ); document.write( "

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