document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=40046>Question 40046</A>: <I><SPAN STYLE=\"word-break: break-all;\"> result in simplest form\r<BR>\n" );
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document.write( "3    1/3\r<BR>\n" );
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document.write( "divide\r<BR>\n" );
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document.write( "2   2/3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #25458 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=25458\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3 1/3 divided by 2 2/3<BR>\n" );
document.write( "Let us change both to improper fractions first...so we get<BR>\n" );
document.write( "10/3 divided by 8/3<BR>\n" );
document.write( "Then flip (or invert) the second number and change it to a multiplication problem...giving us<BR>\n" );
document.write( "10/3 * 3/8 =<BR>\n" );
document.write( "now cancel threes and get<BR>\n" );
document.write( "10/8 = 5/4 or 1 1/4 </SPAN>\n" );
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