document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=356622>Question 356622</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Roberto invested some money at 8%. and then invested $5000 more than twice this amount at 12%. His total annual income from the two investments was $4440. How much was invested at 12%? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #254556 by </B><A HREF=/tutors/aboutme.mpl?userid=robertb><B>robertb(5830)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=robertb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=robertb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=254556\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let x = amount invested at 8%.  Then the amount invested at 12% is 2x + 5000, from the given.  Then <BR>\n" );
document.write( "0.08x + 0.12(2x + 5000) = 4440.<BR>\n" );
document.write( "0.08x+0.24x + 600 = 4440.<BR>\n" );
document.write( "0.32x = 3840<BR>\n" );
document.write( "x = 12,000.  Thus the amount invested at 12 is $29,000. </SPAN>\n" );
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