document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=356620>Question 356620</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 3x+y=10<BR>\n" );
document.write( "y=-2x+4\r<BR>\n" );
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document.write( "solve this by using substitution </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #254555 by </B><A HREF=/tutors/aboutme.mpl?userid=robertb><B>robertb(5830)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=robertb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=robertb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=254555\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Substitute the bottom equation into the top equation:<BR>\n" );
document.write( "3x+(-2x+4)=10.<BR>\n" );
document.write( "3x-2x+4 = 10.<BR>\n" );
document.write( "x = 6.  Then<BR>\n" );
document.write( "y = -2(6) + 4 = -12+4 = -8. </SPAN>\n" );
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