document.write( "Question 356612: Fred walks 3 miles an hour. John walks 2 miles an hour. If they live 4 miles apart, and leave their house at the same time, when will they meet? \n" ); document.write( "
Algebra.Com's Answer #254548 by mananth(16946)\"\" \"About 
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Fred walks 3 miles an hour. John walks 2 miles an hour. If they live 4 miles apart, and leave their house at the same time, when will they meet?
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\n" ); document.write( "fred = 3mph
\n" ); document.write( "john = 2mph
\n" ); document.write( "they walk towards each other
\n" ); document.write( "so their effective speed = 3+2 = 5mph
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\n" ); document.write( "distance = 4 miles
\n" ); document.write( "time = distance / speed
\n" ); document.write( "4/5 hours
\n" ); document.write( "=48 minutes
\n" ); document.write( "...
\n" ); document.write( "m.ananth@hotmail.ca
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