document.write( "Question 356607: at the beginning of a bicycle ride for charity, roberto and juana are 30 miles apart. If they Leave at the same time and ride in the same direction, roberto overtakes juana in 6 hours. if they ride toward each other, they meet in 1 hour. what are their speeds? \n" ); document.write( "
Algebra.Com's Answer #254546 by mananth(16946)\"\" \"About 
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at the beginning of a bicycle ride for charity, roberto and juana are 30 miles apart. If they Leave at the same time and ride in the same direction, roberto overtakes juana in 6 hours. if they ride toward each other, they meet in 1 hour. what are their speeds?
\n" ); document.write( "let robreto's speed =x
\n" ); document.write( "juana's speed =y : x>y
\n" ); document.write( "distance = 30 miles apart
\n" ); document.write( "...
\n" ); document.write( "roberto catches up x=y mph
\n" ); document.write( "distance = speed * time
\n" ); document.write( "30=(x-y)*6
\n" ); document.write( "/6
\n" ); document.write( "x-y =5.....................1
\n" ); document.write( "...
\n" ); document.write( "when they ride toward the speed is x+ymph
\n" ); document.write( "distance = 30
\n" ); document.write( "distance = speed * time
\n" ); document.write( "30=1*(x+y)
\n" ); document.write( "x+y=30....................2
\n" ); document.write( "add 1 & 2
\n" ); document.write( "2x=35
\n" ); document.write( "/2
\n" ); document.write( "x= 35/2
\n" ); document.write( "= 17.5 mph robert's speed
\n" ); document.write( "...
\n" ); document.write( "x-y = 5
\n" ); document.write( "17.5-y=5
\n" ); document.write( "y=17.5-5
\n" ); document.write( "y=12.5 mph Juana's speed
\n" ); document.write( "...
\n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( "
\n" );