document.write( "Question 356578: Butch starts walking from point A at 2 miles per hour. One-half hour later, Dick starts walking from point A at 3.5 miles per hour and follows the same route. How long will it take Dick to catch up with Butch? \n" ); document.write( "
Algebra.Com's Answer #254524 by mananth(16946)![]() ![]() You can put this solution on YOUR website! Butch starts walking from point A at 2 miles per hour. One-half hour later, Dick starts walking from point A at 3.5 miles per hour and follows the same route. How long will it take Dick to catch up with Butch? \n" ); document.write( ".. \n" ); document.write( "speed of Butch = 2 mph \n" ); document.write( "speed of Dick = 3.5 mph. \n" ); document.write( "Dick gains 3.5 -2 = 1.5 mph. \n" ); document.write( ".. \n" ); document.write( "Butch starts 1 1/2 hour early. \n" ); document.write( "so he has traveled 3/2 * 2 = 3 miles when Dick starts. \n" ); document.write( ".. \n" ); document.write( "dick gains 1.5 mph \n" ); document.write( ".. \n" ); document.write( "time = distance / speed \n" ); document.write( "3/1.5 = 2 hours to catch up \n" ); document.write( "... \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " |