document.write( "Question 356578: Butch starts walking from point A at 2 miles per hour. One-half hour later, Dick starts walking from point A at 3.5 miles per hour and follows the same route. How long will it take Dick to catch up with Butch? \n" ); document.write( "
Algebra.Com's Answer #254524 by mananth(16946)\"\" \"About 
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Butch starts walking from point A at 2 miles per hour. One-half hour later, Dick starts walking from point A at 3.5 miles per hour and follows the same route. How long will it take Dick to catch up with Butch?
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\n" ); document.write( "speed of Butch = 2 mph
\n" ); document.write( "speed of Dick = 3.5 mph.
\n" ); document.write( "Dick gains 3.5 -2 = 1.5 mph.
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\n" ); document.write( "Butch starts 1 1/2 hour early.
\n" ); document.write( "so he has traveled 3/2 * 2 = 3 miles when Dick starts.
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\n" ); document.write( "dick gains 1.5 mph
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\n" ); document.write( "time = distance / speed
\n" ); document.write( "3/1.5 = 2 hours to catch up
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\n" ); document.write( "m.ananth@hotmail.ca
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