document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=356548>Question 356548</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A bar of metal contains 10% silver. Another bar contains 15% silver. How many kilograms of each must be taken to make a 10-kg bar containing 12% silver? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #254504 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=254504\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A bar of metal contains 10% silver. Another bar contains 15% silver. How many kilograms of each must be taken to make a 10-kg bar containing 12% silver?<BR>\n" );
document.write( "----------------------<BR>\n" );
document.write( "Equation:<BR>\n" );
document.write( "silver + silver = silver<BR>\n" );
document.write( "0.10x + 0.14(10-x) = 0.12(10)<BR>\n" );
document.write( "-----<BR>\n" );
document.write( "Multiply thru by 100 to get:<BR>\n" );
document.write( "10x + 14*10 - 14x = 12*10<BR>\n" );
document.write( "-4x = -2*10<BR>\n" );
document.write( "x = 5 kg (amt. of 10% bar needed in the mixture)<BR>\n" );
document.write( "---<BR>\n" );
document.write( "10-x = 5 kg (amt of 15% bar needed in the mixture)<BR>\n" );
document.write( "============================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "=========== </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );