document.write( "Question 356464: how much 40% alcohol solution and 25% solution must be mixed together to get 24 gallons of 30% solution? \n" ); document.write( "
Algebra.Com's Answer #254458 by Fombitz(32388)\"\" \"About 
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\n" ); document.write( "Let A be the amount of 40% solution, B the amount of 25% solution.
\n" ); document.write( "Volume:
\n" ); document.write( "1.\"A%2BB=24\"
\n" ); document.write( "Concentration:
\n" ); document.write( "\"40A%2B25B=30%2824%29\"
\n" ); document.write( "2.\"8A%2B5B=144\"
\n" ); document.write( "Multiply eq. 1 by (-5) and add to eq. 2 to eliminate B and solve for A.
\n" ); document.write( "\"-5A-5B%2B8A%2B5B=-120%2B144\"
\n" ); document.write( "\"3A=24\"
\n" ); document.write( "\"highlight%28A=8%29\"gallons
\n" ); document.write( "Then from eq. 1,
\n" ); document.write( "\"8%2BB=24\"
\n" ); document.write( "\"highlight%28B=16%29\"gallons
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