document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=356435>Question 356435</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Would you help me?  Thank you!<BR>\n" );
document.write( "Logarithm\r<BR>\n" );
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document.write( "Write the inverse for the function of y+2=4^(x-1) in the form y=.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #254445 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=254445\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Write the inverse for the function of <BR>\n" );
document.write( "y+2=4^(x-1) in the form y=.<BR>\n" );
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document.write( "1st: Interchange x and y to get:<BR>\n" );
document.write( "x + 2 = 4^(y-1)<BR>\n" );
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document.write( "2nd: Solve for \"y\":<BR>\n" );
document.write( "Take the log of both sides to get:<BR>\n" );
document.write( "(y-1)*log(4) = log(x+2)<BR>\n" );
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document.write( "y-1 = [log(x+2)/log(4)]<BR>\n" );
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document.write( "y = [log(x+2)/log(4)] + 1<BR>\n" );
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document.write( "That is the inverse.<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.\r<BR>\n" );
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