document.write( "Question 356417: A dealer purchased a number of equally priced articles for a total cost of £120. She sold all but one of them, making a profit of £1.50 on each article with a total revenue of £135. How many articles did she purchase? \n" ); document.write( "
Algebra.Com's Answer #254440 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A dealer purchased a number of equally priced articles for a total cost of £120. She sold all but one of them, making a profit of £1.50 on each article with a total revenue of £135. How many articles did she purchase? \n" ); document.write( "------ \n" ); document.write( "Let the original number of articles be \"x\". \n" ); document.write( "Average price of those x items = 120/x \n" ); document.write( "------------------------ \n" ); document.write( "Equation: \n" ); document.write( "(x-1)[(120/x)+1.50] = 135 \n" ); document.write( "---- \n" ); document.write( "120 +1.5x - (120/x)-1.5 = 135 \n" ); document.write( "118.5 + 1.5x - 120/x = 135 \n" ); document.write( "1.5x -120/x - 16.5 = 0 \n" ); document.write( "1.5x^2 -16.5x - 120 = 0 \n" ); document.write( "x^2 - 11x - 80 = 0 \n" ); document.write( "(x+5)(x-16) = 0 \n" ); document.write( "Positive solution: \n" ); document.write( "x = 16 articles \n" ); document.write( "====================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |