document.write( "Question 356417: A dealer purchased a number of equally priced articles for a total cost of £120. She sold all but one of them, making a profit of £1.50 on each article with a total revenue of £135. How many articles did she purchase? \n" ); document.write( "
Algebra.Com's Answer #254440 by stanbon(75887)\"\" \"About 
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A dealer purchased a number of equally priced articles for a total cost of £120. She sold all but one of them, making a profit of £1.50 on each article with a total revenue of £135. How many articles did she purchase?
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\n" ); document.write( "Let the original number of articles be \"x\".
\n" ); document.write( "Average price of those x items = 120/x
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\n" ); document.write( "Equation:
\n" ); document.write( "(x-1)[(120/x)+1.50] = 135
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\n" ); document.write( "120 +1.5x - (120/x)-1.5 = 135
\n" ); document.write( "118.5 + 1.5x - 120/x = 135
\n" ); document.write( "1.5x -120/x - 16.5 = 0
\n" ); document.write( "1.5x^2 -16.5x - 120 = 0
\n" ); document.write( "x^2 - 11x - 80 = 0
\n" ); document.write( "(x+5)(x-16) = 0
\n" ); document.write( "Positive solution:
\n" ); document.write( "x = 16 articles
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.\r
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