document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=356404>Question 356404</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if the volume of a cone is 3692.64 cm^3 and the hieght of the cone is 18 cm, what would be the area of the base of the cone? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #254424 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=254424\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=Vol+=+pi%2Ar%5E2%2Ah%2F3+=+area%2Ah%2F3 ALIGN=MIDDLE  ALT=\"Vol+=+pi%2Ar%5E2%2Ah%2F3+=+area%2Ah%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "area = 3*Vol/h = 3*3692.64/18<BR>\n" );
document.write( "area = 615.44 sq cm<BR>\n" );
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