document.write( "Question 356190: At the north campus of a small liberal arts college, 10% of the students are women. At the south campus, 50% of the students are women. The campuses are merged into one east campus. If 40% of the 1200 students at the east campus are women, how many students did each of the north and south campuses have before the merger? \n" ); document.write( "
Algebra.Com's Answer #254328 by jrfrunner(365)![]() ![]() You can put this solution on YOUR website! At the north campus of a small liberal arts college, 10% of the students are women. At the south campus, 50% of the students are women. The campuses are merged into one east campus. If 40% of the 1200 students at the east campus are women, how many students did each of the north and south campuses have before the merger? \n" ); document.write( "== \n" ); document.write( "let N=total students at North campus \n" ); document.write( "Let S=total students at South campus \n" ); document.write( "-- \n" ); document.write( "given \n" ); document.write( "North campus merged with South campus to create east campus of 1200 students \n" ); document.write( "eq 1, total students: N+S=1200 \n" ); document.write( "eq 2, women: 0.10N+0.50S=0.40*1200=480 \n" ); document.write( "-- \n" ); document.write( "step 1: N+5S=4800 multiply eq 2 by 10 \n" ); document.write( "step 2: N=1200-S solve for N in eq1 \n" ); document.write( "step 3: (1200-S)+5S=4800 substitute step 2 into step 1 \n" ); document.write( "step 4: 4S=3600 group similar terms \n" ); document.write( "step 5: S=900 \n" ); document.write( "step 6: N=1200-S therefore N=1200-900=300 \n" ); document.write( "== \n" ); document.write( "validate \n" ); document.write( "go to eq1 and eq2 substitute S=900 and N=300 \n" ); document.write( "N+S=300+900=1200 checked \n" ); document.write( "0.1N+0.5S=480 ==> 0.1*300+0.5*900=30+450=480 checked \n" ); document.write( "== \n" ); document.write( "answer \n" ); document.write( " \n" ); document.write( " |