document.write( "Question 356190: At the north campus of a small liberal arts college, 10% of the students are women. At the south campus, 50% of the students are women. The campuses are merged into one east campus. If 40% of the 1200 students at the east campus are women, how many students did each of the north and south campuses have before the merger? \n" ); document.write( "
Algebra.Com's Answer #254328 by jrfrunner(365)\"\" \"About 
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At the north campus of a small liberal arts college, 10% of the students are women. At the south campus, 50% of the students are women. The campuses are merged into one east campus. If 40% of the 1200 students at the east campus are women, how many students did each of the north and south campuses have before the merger?
\n" ); document.write( "==
\n" ); document.write( "let N=total students at North campus
\n" ); document.write( "Let S=total students at South campus
\n" ); document.write( "--
\n" ); document.write( "given
\n" ); document.write( "North campus merged with South campus to create east campus of 1200 students
\n" ); document.write( "eq 1, total students: N+S=1200
\n" ); document.write( "eq 2, women: 0.10N+0.50S=0.40*1200=480
\n" ); document.write( "--
\n" ); document.write( "step 1: N+5S=4800 multiply eq 2 by 10
\n" ); document.write( "step 2: N=1200-S solve for N in eq1
\n" ); document.write( "step 3: (1200-S)+5S=4800 substitute step 2 into step 1
\n" ); document.write( "step 4: 4S=3600 group similar terms
\n" ); document.write( "step 5: S=900
\n" ); document.write( "step 6: N=1200-S therefore N=1200-900=300
\n" ); document.write( "==
\n" ); document.write( "validate
\n" ); document.write( "go to eq1 and eq2 substitute S=900 and N=300
\n" ); document.write( "N+S=300+900=1200 checked
\n" ); document.write( "0.1N+0.5S=480 ==> 0.1*300+0.5*900=30+450=480 checked
\n" ); document.write( "==
\n" ); document.write( "answer \"highlight_red%28N=300%29\", \"highlight_red%28S=900%29\"
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