document.write( "Question 356235: karen is 3 times as old as Bill, and Bill is 2 years younger than Janice. Six years ago Karen was 2.5 times the age that Janice is now. How old is each person now? \n" ); document.write( "
Algebra.Com's Answer #254279 by mananth(16946)![]() ![]() You can put this solution on YOUR website! karen is 3 times as old as Bill, and Bill is 2 years younger than Janice. Six years ago Karen was 2.5 times the age that Janice is now. How old is each person now?\r \n" ); document.write( "\n" ); document.write( "... \n" ); document.write( "Janice be x years now \n" ); document.write( "Bill will be x-2 years \n" ); document.write( "Karen is 3(x-2) \n" ); document.write( "... \n" ); document.write( "six years ago karen will be \n" ); document.write( "3(x-2)-6 years \n" ); document.write( "... \n" ); document.write( "3(x-2)-6 = 2.5x \n" ); document.write( "3x-6-6=2.5x \n" ); document.write( "3x-2.5x=12 \n" ); document.write( "0.5x=12 \n" ); document.write( "/0.5 \n" ); document.write( "x= 24 janice's age now \n" ); document.write( ".. \n" ); document.write( "bill = x-2 = 22 \n" ); document.write( ".. \n" ); document.write( "Karen = 3(x-2) = 3(48-2) \n" ); document.write( "=66 years \n" ); document.write( "... \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " \n" ); document.write( " |