document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=356202>Question 356202</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Dad is 42 years old and his son is 10. In how many years will Dad be 3 times as old as his son? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #254261 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=254261\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let the number of years after which dad is 3 times be x<BR>\n" );
document.write( "42+x = 3(10+x)<BR>\n" );
document.write( "42+x = 30+3x<BR>\n" );
document.write( "42-30=3x-x<BR>\n" );
document.write( "12=2x<BR>\n" );
document.write( "x=6 after 6 years.<BR>\n" );
document.write( "...<BR>\n" );
document.write( "m.ananth@hotmail.ca </SPAN>\n" );
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