document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=356108>Question 356108</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please someone help me. I am trying to help my 7th grader with is algebra 1 homework. Here is the problem. The width of a rectangle is one half its length. The perimeter of the rectangle is 24 inches. What are the width and length of the rectangle? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #254241 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=254241\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> w=L/2<BR>\n" );
document.write( "L=2w<BR>\n" );
document.write( "P=24\"<BR>\n" );
document.write( "P=2L+2w<BR>\n" );
document.write( "2*2w+2w=24 Substitute 2w for L<BR>\n" );
document.write( "6w=24<BR>\n" );
document.write( "w=4\"<BR>\n" );
document.write( "L=8\"<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Ed </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );