document.write( "Question 356136: perimeter of a rectangle is 204 inches. the length exceeds the width by 62 inches. what is the length and width? \n" ); document.write( "
Algebra.Com's Answer #254202 by mananth(16946)![]() ![]() You can put this solution on YOUR website! width be x \n" ); document.write( "length = x+62 \n" ); document.write( ".. \n" ); document.write( "2*(L+W)=204 \n" ); document.write( "2*(x+x+62)=204 \n" ); document.write( "2*(2x+62)=204 \n" ); document.write( "divide by2 \n" ); document.write( "2x+62=102 \n" ); document.write( "2x=102-62 \n" ); document.write( "2x=40 \n" ); document.write( "/2 \n" ); document.write( "x= 20 the width \n" ); document.write( "length = x+62 = 20+62 \n" ); document.write( "=82 \n" ); document.write( "... \n" ); document.write( ". \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " \n" ); document.write( " |