document.write( "Question 356136: perimeter of a rectangle is 204 inches. the length exceeds the width by 62 inches. what is the length and width? \n" ); document.write( "
Algebra.Com's Answer #254202 by mananth(16946)\"\" \"About 
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width be x
\n" ); document.write( "length = x+62
\n" ); document.write( "..
\n" ); document.write( "2*(L+W)=204
\n" ); document.write( "2*(x+x+62)=204
\n" ); document.write( "2*(2x+62)=204
\n" ); document.write( "divide by2
\n" ); document.write( "2x+62=102
\n" ); document.write( "2x=102-62
\n" ); document.write( "2x=40
\n" ); document.write( "/2
\n" ); document.write( "x= 20 the width
\n" ); document.write( "length = x+62 = 20+62
\n" ); document.write( "=82
\n" ); document.write( "...
\n" ); document.write( ".
\n" ); document.write( "m.ananth@hotmail.ca
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