document.write( "Question 356042: Consider the function j(x)=(square root of x)squared.\r
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\n" ); document.write( "\n" ); document.write( "(b) Find the range of j using the natural domain.\r
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Algebra.Com's Answer #254138 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
a) The domain of \"sqrt%28x%29\" is \"x%3E=0\" since you can't take the square root of a negative number. So the domain of \"j%28x%29=%28sqrt%28x%29%29%5E2\" is also \"x%3E=0\"\r
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\n" ); document.write( "\n" ); document.write( "b) To find the range, you can either graph \"j%28x%29=%28sqrt%28x%29%29%5E2\" and note the possible y values, or you can find the inverse function and find the domain of that inverse function. Either way, you'll find that the range is \"j%28x%29%3E=0\"
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