document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=355997>Question 355997</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi there!\r<BR>\n" );
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document.write( "I am in an Intermediate Algebra class and am so confused when it comes to, well, several things (hehehe... everything else is a project for another day=)\r<BR>\n" );
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document.write( "I am currently having difficulties writing equations as functions. I understand f(x) = y... I also understand that y needs to be solved. The equation I am working with is:\r<BR>\n" );
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document.write( "3x+5y=15\r<BR>\n" );
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document.write( "I don't necessarily need the answer... It is answered in my text. I am trying to figure out how to come to the solution myself (in Laymens terms so to speak). (Text answer is f(x)= -3/5x+3).\r<BR>\n" );
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document.write( "Any insight you can provide would be GREATLY appreciated! Thank you very much!\r<BR>\n" );
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document.write( "Sincerely:<BR>\n" );
document.write( "Gina G<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #254117 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=254117\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> like you said ... f(x) = y\r<BR>\n" );
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document.write( "subtracting 3x ___ 5y = -3x + 15\r<BR>\n" );
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document.write( "dividing by 5 ___ y = (-3/5)x + 3\r<BR>\n" );
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document.write( "this comes from graphing , where the independent variable (x) is graphed on the horizontal axis<BR>\n" );
document.write( "___ and the dependent variable (y or f(x)) is graphed on the vertical axis\r<BR>\n" );
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document.write( "the value of the dependent variable depends on (is a function of) the value of the independent variable </SPAN>\n" );
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