document.write( "Question 355854: A man has $1.15 made up of six American coins. With these coins, however, he cannot make change of a dollar, nor of a half dollar, a quarter, a dime or a nickel. Which six coins does he have? \n" ); document.write( "
Algebra.Com's Answer #254116 by Edwin McCravy(20059)![]() ![]() You can put this solution on YOUR website! \r\n" ); document.write( "You obviously can't have any pennies, because you couldn't have 1-4 pennies,\r\n" ); document.write( "since $1.15 is a multiple of 5, and if you had 5 pennies or more you could\r\n" ); document.write( "change a nickel. \r\n" ); document.write( "\r\n" ); document.write( "You can't have more than 1 nickel, otherwise you could change a dime.\r\n" ); document.write( "And if you had 1 nickel you couldn't have but 1 dime, otherwise you could\r\n" ); document.write( "change a quarter. Then if you had 1 nickel and 1 dime you'd have 15 cents.\r\n" ); document.write( "That would leave $1.00 and you couldn't make that remaining $1.00 with quarters\r\n" ); document.write( "and halves without either being able to change a half or a dollar.\r\n" ); document.write( "\r\n" ); document.write( "So you can't have any pennies or nickels.\r\n" ); document.write( "\r\n" ); document.write( "Since you can't have any pennies or nickels, you can't possibly make $1.15 with\r\n" ); document.write( "dimes and halves only, so you must have at least 1 quarter. You can't have\r\n" ); document.write( "more that one quarter, otherwise you could change a half. So you must have\r\n" ); document.write( "exactly 1 quarter. \r\n" ); document.write( "\r\n" ); document.write( "That leaves 90 cents, to make with a half dollar and dimes. So that's 1\r\n" ); document.write( "half and 4 dimes. And with only 4 dimes you can't change a half dollar.\r\n" ); document.write( "\r\n" ); document.write( "So that's the answer: 4 dimes, a quarter and a half dollar. \r\n" ); document.write( "\r\n" ); document.write( "Edwin\n" ); document.write( " |