document.write( "Question 355878: Given that AB = DE and BC = CD show that AD = BE. \n" ); document.write( "
Algebra.Com's Answer #254114 by Fombitz(32388)\"\" \"About 
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\n" ); document.write( "1.\"AB%2BBC%2BCD%2BDE=AE\"
\n" ); document.write( "2.\"AD%2BDE=AE\"
\n" ); document.write( "3.\"AB%2BBE=AE\"
\n" ); document.write( "Given,
\n" ); document.write( "\"AB=DE\"
\n" ); document.write( "\"BC=CD\"
\n" ); document.write( "Substituting into eq. 1,
\n" ); document.write( "\"AB%2BBC%2BBC%2BAB=AE\"
\n" ); document.write( "\"2AB%2B2BC=AE\"
\n" ); document.write( "\"2AC=AE\"
\n" ); document.write( "\"AC=CE=%281%2F2%29AE\"
\n" ); document.write( "Add \"CD\" to both sides.
\n" ); document.write( "\"AC%2BCD=CD%2BCE\"
\n" ); document.write( "Substitute from the given equation,
\n" ); document.write( "\"AC%2BCD=BC%2BCE\"
\n" ); document.write( "So then,
\n" ); document.write( "\"AD=BE\"
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