document.write( "Question 355844: Hi, I'm being asked to solve the inequality and graph on a number line. I'm new to this, so I'm wondering do I treat the inequality as an equation and complete the square?\r
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document.write( "x^2 + x - 9 > 3\r
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document.write( "x^2 + x + .25 > 12\r
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document.write( "(x + .5)^2 > 12\r
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document.write( "x > -.5 +/- sqrt(12)\r
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document.write( "Would this be correct? I'm getting x > 2.96 and x > -3.96, and not sure how I would put this on a number line. Any guidance you can provide is greatly appreciated!
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Algebra.Com's Answer #254067 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! x^2 + x - 9 > 3\r \n" ); document.write( "\n" ); document.write( "x^2 + x + .25 > 12.25 (not 12)\r \n" ); document.write( "\n" ); document.write( "(x + .5)^2 > 12.25\r \n" ); document.write( "\n" ); document.write( "x > -.5 +/- 3.5 \r \n" ); document.write( "\n" ); document.write( "Would this be correct? I'm getting x > 2.96 and x > -3.96 \n" ); document.write( "---------------- \n" ); document.write( "x^2 + x - 9 > 3 \n" ); document.write( "x^2 + x - 12 > 0 \n" ); document.write( "(x+4)*(x-3) > 0 \n" ); document.write( "For the product to be > 0, the terms have to have the same signs. \n" ); document.write( "-------------- \n" ); document.write( "(x+4) & (x-3) > 0 --> x > 3 (that makes it > -4) \n" ); document.write( "or, \n" ); document.write( "(x+4) & (x-3) < 0 --> x < -4 (which is less than +3) \n" ); document.write( "--> x < -4 or x > 3 \n" ); document.write( "--> x is all real numbers except from -4 to +3 inclusive \n" ); document.write( " \n" ); document.write( " |