document.write( "Question 39984: log4(2x+3)-logx=3 \n" ); document.write( "
Algebra.Com's Answer #25404 by fractalier(6550) You can put this solution on YOUR website! Assuming these are logs to the base ten, we have \n" ); document.write( "log4(2x+3) - logx = 3 \n" ); document.write( "log (8x+12 / x) = 3 \n" ); document.write( "8x + 12 / x = 1000 \n" ); document.write( "8x + 12 = 1000x \n" ); document.write( "12 = 992x \n" ); document.write( "x = 12/992 = 1/82 \n" ); document.write( " |