document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=355744>Question 355744</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need help solving the following systems.  Please show the work so that I can understand for future reference.  Thanks in advance for any help.\r<BR>\n" );
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document.write( "x+3/2y=7/2<BR>\n" );
document.write( "3x=3/4y </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #254037 by </B><A HREF=/tutors/aboutme.mpl?userid=J2R2R><B>J2R2R(94)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=J2R2R><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=J2R2R><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=254037\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">                     x + 3/2y = 7/2\r<BR>\n" );
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document.write( "                    3x = 3/4y\r<BR>\n" );
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document.write( "From the second equation we have\r<BR>\n" );
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document.write( "                     x = y/4\r<BR>\n" );
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document.write( "So substituting this into the first equation we have\r<BR>\n" );
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document.write( "                     y/4 + 3y/2 = 7/2\r<BR>\n" );
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document.write( "x 4                 y + 6y = 14\r<BR>\n" );
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document.write( "                     7y = 14\r<BR>\n" );
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document.write( "                      y = 2\r<BR>\n" );
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document.write( "Giving x = y/4 = 2/4 = 1/2\r<BR>\n" );
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document.write( "Check\r<BR>\n" );
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document.write( "                    1/2 + 3 = 7/2\r<BR>\n" );
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document.write( "                    3/2 = 6/4 </SPAN>\n" );
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