document.write( "Question 355674: a woman with a basket of eggs finds that if she removes the eggs from the basket either two, three, four, five, or six at a time, there is always one egg left.however, if she removes the eggs by seven at a time, there are no eggs left. if the basket holds at least 300 eggs, how many eggs are in the woman's basket? \n" ); document.write( "
Algebra.Com's Answer #254025 by Theo(13342)\"\" \"About 
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she has to have a minimum of 300 eggs.
\n" ); document.write( "300 / 7 = 42.something
\n" ); document.write( "42*7 = 294
\n" ); document.write( "294 + 7 = 301
\n" ); document.write( "she has to have at least 301 eggs.
\n" ); document.write( "all the other number have to divide evenly into 300
\n" ); document.write( "7 needs to divide evenly into 301
\n" ); document.write( "301/7 = 43
\n" ); document.write( "300/6 = 50
\n" ); document.write( "300/5 = 60
\n" ); document.write( "300/4 = 75
\n" ); document.write( "300/3 = 100
\n" ); document.write( "300/2 = 150\r
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\n" ); document.write( "\n" ); document.write( "Your number is 301.\r
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