document.write( "Question 355635: What s the answer to the following question:\r
\n" ); document.write( "\n" ); document.write( "Estimate the proportion of observations falling within 1.2 standard deviations from the mean on a normal distribution. \n" ); document.write( "

Algebra.Com's Answer #254012 by Fombitz(32388) $\"\"$ $\"About$

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In other words what is the area of the distribution curve between ( $\"-1.2%2Asigma\"$ , $\"+1.2%2Asigma\"$ ).
\n" ); document.write( "Find $\"P%281.2%29=0.11507\"$ .
\n" ); document.write( "That's the area of the region up to $\"1.2%2Asigma\"$ .
\n" ); document.write( "The area from there to $\"x=0\"$ would then be,
\n" ); document.write( " $\"A=0.5-0.11507\"$
\n" ); document.write( " $\"A=0.38493\"$
\n" ); document.write( "Twice that area would give us the area from ( $\"-1.2%2Asigma\"$ , $\"+1.2%2Asigma\"$ ).
\n" ); document.write( " $\"A=0.769861\"$ \n" ); document.write( "

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