document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=355705>Question 355705</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Regarding Products of Sums and Differences<BR>\n" );
document.write( "Multiply and simplify (3xy^2+4y)(-3xy^2+4y)\r<BR>\n" );
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document.write( "1) Please show me the steps to solving this. I have tried numberous times and do not get the answer the book shows. \r<BR>\n" );
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document.write( "2)Why is commutative law used? How should I know when to use it? Why are they switched? How should I know on my own when to switch them? The book shows the first step goes to (4y+3xy^2) (4y-3xy^2). I do not understand that at all.\r<BR>\n" );
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document.write( "I appreciate any help.<BR>\n" );
document.write( "Jill </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #253995 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=253995\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (4y+3xy^2) (4y-3xy^2)<BR>\n" );
document.write( "to put in simple terms you have to multiply each term in one bracket with the other terms in the second bracket.<BR>\n" );
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document.write( "4y(4y-3xy^2)+3xy^2(4y-3xy^2)<BR>\n" );
document.write( "now you have to multiply the term outside the bracket with the terms in the bracket.( distributive law)<BR>\n" );
document.write( "...<BR>\n" );
document.write( "4y*4y-4y*3xy^2+3xy^2*4y-3xy^2*3xy^2<BR>\n" );
document.write( "16y^2-12xy^3+12xy^3-9x^2y^4<BR>\n" );
document.write( "16y^2-9x^2y^4<BR>\n" );
document.write( "..<BR>\n" );
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