document.write( "Question 355601: Please help me solve this equation:\r
\n" );
document.write( "\n" );
document.write( "a) Differentiate DO NOT SIMPLIFY
\n" );
document.write( "
\n" );
document.write( "b) Simplify \n" );
document.write( "
Algebra.Com's Answer #253977 by jsmallt9(3758) ![]() You can put this solution on YOUR website! \n" ); document.write( "This problem uses the several levels of the chain rule. First we will \n" ); document.write( "Let u = \n" ); document.write( "This makes f = u/v and from this we know that \n" ); document.write( "f' = (v*u' - u*v')/v^2 \n" ); document.write( "For this we will need u' and v': \n" ); document.write( "u' = \n" ); document.write( "Since the derivative of \n" ); document.write( "u' = \n" ); document.write( "and v' = \n" ); document.write( "Substituting u, u', v and v' into the f' equation we get: \n" ); document.write( "f' = \n" ); document.write( "And if you're not supposed to simplify, then I guess this mess is an acceptable answer. \n" ); document.write( "b) \n" ); document.write( "For this one, picture a right triangle. For one of the acute angles we want the tangent to be 2x. In other words we want the ratio of opposite/adjacent to be 2x. An opposite side of 2x and an adjacent side of 1 would give us this ratio. We want to find the sin of this angle. Since sin is opposite/hypotenuse, we will need an expression for the hypotenuse. For this we can use the Pythagorean Theorem: \n" ); document.write( "Opposite^2 + Adjacent^2 = Hypotenuse^2 \n" ); document.write( "Putting our expressions for the opposite side and adjacent side into this we get: \n" ); document.write( " \n" ); document.write( "which simplifies to: \n" ); document.write( " \n" ); document.write( "So the Hypotenuse is \n" ); document.write( "Now we can express the sin ratio: \n" ); document.write( " |