document.write( "Question 355636: Please Help me solve this problem.
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document.write( "Maylen is 20 years older than her daughter Hazel. In ten years time she will be twice as old as her daughter. How old are Maylene and Hazel ?
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document.write( "Thanks ~ \n" );
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Algebra.Com's Answer #253949 by mananth(16946)![]() ![]() You can put this solution on YOUR website! let hazel be x years \n" ); document.write( "maylene = x+20 \n" ); document.write( "... \n" ); document.write( "ten years later their ages will be \n" ); document.write( "hazel = x+10 \n" ); document.write( "Maylene = x+20+10=x+30 \n" ); document.write( "x+30=2(x+10) \n" ); document.write( "x+30 = 2x+20 \n" ); document.write( "2x-x=20-10 \n" ); document.write( "x=10 hazels age \n" ); document.write( "Maylene = x+20 \n" ); document.write( "Maylene will be 30 years \n" ); document.write( "... \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " \n" ); document.write( " |