document.write( "Question 355636: Please Help me solve this problem.
\n" ); document.write( "Maylen is 20 years older than her daughter Hazel. In ten years time she will be twice as old as her daughter. How old are Maylene and Hazel ?
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Algebra.Com's Answer #253949 by mananth(16946)\"\" \"About 
You can put this solution on YOUR website!
let hazel be x years
\n" ); document.write( "maylene = x+20
\n" ); document.write( "...
\n" ); document.write( "ten years later their ages will be
\n" ); document.write( "hazel = x+10
\n" ); document.write( "Maylene = x+20+10=x+30
\n" ); document.write( "x+30=2(x+10)
\n" ); document.write( "x+30 = 2x+20
\n" ); document.write( "2x-x=20-10
\n" ); document.write( "x=10 hazels age
\n" ); document.write( "Maylene = x+20
\n" ); document.write( "Maylene will be 30 years
\n" ); document.write( "...
\n" ); document.write( "m.ananth@hotmail.ca
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