document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=355656>Question 355656</A>: <I><SPAN STYLE=\"word-break: break-all;\"> What is the measure of an angle if the measure of its supplement is 39 degree more than twice the measure of its complement? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #253948 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=253948\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let the angle be x<BR>\n" );
document.write( "the complement will be 90-x deg<BR>\n" );
document.write( "the supplement = 180-x<BR>\n" );
document.write( "..<BR>\n" );
document.write( "180-x = 2(90-x)+39<BR>\n" );
document.write( "180-x=180-2x+39<BR>\n" );
document.write( "180-180-39=-2x+x<BR>\n" );
document.write( "-x=-39<BR>\n" );
document.write( "x= 39 the measure of the angle<BR>\n" );
document.write( "..<BR>\n" );
document.write( "m.ananth@hotmail.ca </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );