document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=355624>Question 355624</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A running track has the shape with straight sides and semicircular ends. if the length of the track is 440 yd the two straight parts are each 110 yd long, what is the radius of the semicircular parts(to the nearest yd)? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #253932 by </B><A HREF=/tutors/aboutme.mpl?userid=robertb><B>robertb(5830)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=robertb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=robertb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=253932\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the two straight parts are each 110 yards.  Thus each of the two congruent semicircular parts must also be 110 yards each.  Now circumference <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=C+=+2%2Api%2Ar ALIGN=MIDDLE  ALT=\"C+=+2%2Api%2Ar\"   DISABLED_style= \"max-width:90%; height:auto;\" >, or <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=C%2F2+=+pi%2Ar ALIGN=MIDDLE  ALT=\"C%2F2+=+pi%2Ar\"   DISABLED_style= \"max-width:90%; height:auto;\" >.  This means that <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=110+=+pi%2Ar ALIGN=MIDDLE  ALT=\"110+=+pi%2Ar\"   DISABLED_style= \"max-width:90%; height:auto;\" >, or <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=r+=+110%2Fpi ALIGN=MIDDLE  ALT=\"r+=+110%2Fpi\"   DISABLED_style= \"max-width:90%; height:auto;\" >.  To the nearest yard, this is equal to 35 yards. </SPAN>\n" );
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