document.write( "Question 355589: If A and B are independent events, P(A) = 0.4, and P(B) = 0.6, find the probabilities below.\r
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document.write( "(a) P(A intersection B)\r
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document.write( "(b) P(A union B) \n" );
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Algebra.Com's Answer #253916 by nyc_function(2741)![]() ![]() You can put this solution on YOUR website! P(A intersection B) = probability involving AND.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "P(A intersection B) = P(A) + P(B)\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "P(A intersection B) = 0.4 + 0.6\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "P(A intersection B) = 1.0 or simply 1.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "======================================\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " P(A union B) = probability involving OR.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " P(A union B) = P(A) + P(B) - P(A intersection B)\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "P(A union B) = 0.4 + 0.6 - 1.0\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "P(A union B) = 1.0 - 1.0\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "P(A union B) = 0\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "I hope this helps.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |