document.write( "Question 355462: write an equation of the line that passes through ( 6,-10) and is perpendicular to the line that passes through ( 4,-6) and (3,-4) \n" ); document.write( "

Algebra.Com's Answer #253871 by robertb(5830) $\"\"$ $\"About$

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The slope of the line pasing through (4,-6) and (3, -4) is
\n" ); document.write( " $\"%28-4-%28-6%29%29%2F%283-4%29+=+2%2F%28-1%29=+-2\"$ . The slope of the line perpendicular to this is equal to its negative reciprocal: 1/2. Therefore the equation of the line with slope 1/2 and passing through (6,-10) is
\n" ); document.write( " $\"y-%28-10%29+=+%281%2F2%29%28x-6%29\"$ , or
\n" ); document.write( " $\"y+%2B+10+=+%281%2F2%29%28x-6%29\"$ ,
\n" ); document.write( " $\"y+=+%281%2F2%29x-3-10\"$ ,
\n" ); document.write( " $\"y+=+%281%2F2%29x-13\"$ . \n" ); document.write( "

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