document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=40006>Question 40006</A>: <I><SPAN STYLE=\"word-break: break-all;\"> log(5)625+log(9)(x-3)=6 need help please </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #25386 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=25386\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Okay, from<BR>\n" );
document.write( "log(5)625 + log(9)(x-3) = 6<BR>\n" );
document.write( "let us evaluate the left hand log first...<BR>\n" );
document.write( "we ask, \"What exponent must we raise 5 to to get to 625?\"  Well, 4.  So we have<BR>\n" );
document.write( "4 + log(9)(x-3) = 6<BR>\n" );
document.write( "log(9)(x-3) = 2<BR>\n" );
document.write( "Now convert this to an exponential form...<BR>\n" );
document.write( "9^2 = x - 3<BR>\n" );
document.write( "81 = x - 3<BR>\n" );
document.write( "x = 84 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );