document.write( "Question 355338: Solve the system using the substitution method.\r
\n" ); document.write( "\n" ); document.write( "x + 2y = 6
\n" ); document.write( "3x - 2y = 2\r
\n" ); document.write( "\n" ); document.write( "This is what I did:\r
\n" ); document.write( "\n" ); document.write( "3x - 2y = 2 .... x = -2y - 3
\n" ); document.write( "_______________________________\r
\n" ); document.write( "\n" ); document.write( "(-2y - 3) + 2y = 6
\n" ); document.write( " =
\n" ); document.write( "-2y + 2y = 3
\n" ); document.write( "____________________
\n" ); document.write( "y= 3
\n" ); document.write( "_______________________________
\n" ); document.write( "x = -2y - 3
\n" ); document.write( "x= -2 (3) - 3
\n" ); document.write( "x = -9\r
\n" ); document.write( "\n" ); document.write( "I checked my solution and it was wrong. I don't know where I messed up \n" ); document.write( "

Algebra.Com's Answer #253844 by jerryguo41(197) $\"\"$ $\"About$

You can put this solution on YOUR website!
x + 2y = 6
\n" ); document.write( "3x - 2y = 2
\n" ); document.write( "________________\r
\n" ); document.write( "\n" ); document.write( "x + 2y=6
\n" ); document.write( "y = 1/2x + 3
\n" ); document.write( "________________\r
\n" ); document.write( "\n" ); document.write( "x - 2y = 2
\n" ); document.write( "x - 2(1/2x + 3) = 2
\n" ); document.write( "x - 2x + 6 = 2
\n" ); document.write( "-x = -4
\n" ); document.write( "x = 4
\n" ); document.write( " \n" ); document.write( "

\n" );