document.write( "Question 355242: how many liters of 20% alcohol solution and 10% alcohol solution must be mixed to obtain 50 liters of a 12% alcohol solution? \n" ); document.write( "
Algebra.Com's Answer #253777 by Fombitz(32388)\"\" \"About 
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Let A be the amount of 20% solution, B the amount of 10% solution.
\n" ); document.write( "Total volume:
\n" ); document.write( "1.\"A%2BB=50\"
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\n" ); document.write( "Total concentration:
\n" ); document.write( "\"20A%2B10B=12%2850%29\"
\n" ); document.write( "2.\"2A%2BB=60\"
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\n" ); document.write( "Subtract eq. 1 from eq. 2,
\n" ); document.write( "\"2A%2BB-A-B=60-50\"
\n" ); document.write( "\"highlight%28A=10%29\"liters
\n" ); document.write( "Then from eq. 1,
\n" ); document.write( "\"10%2BB=50\"
\n" ); document.write( "\"highlight%28B=40%29\"liters
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