document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=355236>Question 355236</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help. Don't know how to construct the equation for this problem:<BR>\n" );
document.write( "One can of paint is enough for 3 chairs OR 2 tables. Therefore, 7 cans of paint will be enough for 12 chairs AND how many tables?<BR>\n" );
document.write( "a. 4<BR>\n" );
document.write( "b. 5<BR>\n" );
document.write( "c. 6<BR>\n" );
document.write( "d. 7 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #253776 by </B><A HREF=/tutors/aboutme.mpl?userid=sudhanshu_kmr><B>sudhanshu_kmr(1152)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=sudhanshu_kmr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=sudhanshu_kmr><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=253776\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let paint required for 1 chair is x, and for table y.\r<BR>\n" );
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document.write( "so, 1 can = 3x = 2y  \r<BR>\n" );
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document.write( "or x = 2y/3 ...(1)\r<BR>\n" );
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document.write( "now, using 7 can is enough for 3*7 = 21 chairs = 12x+ 9x\r<BR>\n" );
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document.write( "here we have to convert 9x into terms of y using (1)\r<BR>\n" );
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document.write( "9x =  9 * (2y/3)\r<BR>\n" );
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document.write( "= 6y \r<BR>\n" );
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document.write( "so, answer is 6 tables. </SPAN>\n" );
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