document.write( "Question 354347: Solve. Round to four decimal places\r
\n" ); document.write( "\n" ); document.write( "a) e^3x >_ 21\r
\n" ); document.write( "\n" ); document.write( "b) (1/5)^t-2 = 125
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Algebra.Com's Answer #253774 by jsmallt9(3758)\"\" \"About 
You can put this solution on YOUR website!
a) \"e%5E%283x%29+%3E=+21\"
\n" ); document.write( "Find the natural log (because of the \"e\" and because we want a decimal):
\n" ); document.write( "\"ln%28e%5E%283x%29%29+%3E=+21\"
\n" ); document.write( "Use a property of logarithms, \"log%28a%2C+%28p%5Eq%29%29+=+q%2Alog%28a%2C+%28p%29%29\", to move the exponent out in front:
\n" ); document.write( "\"3x%2Aln%28e%29+%3E=+21\"
\n" ); document.write( "By definition, ln(e) = 1 so this simplifies to:
\n" ); document.write( "\"3x+%3E=+21\"
\n" ); document.write( "Divide both sides by 3:
\n" ); document.write( "\"x+%3E=+21\"

\n" ); document.write( "b) \"%281%2F5%29%5E%28t-2%29+=+125\"
\n" ); document.write( "The quick way to solve this comes from recognizing that both sides are powers of 5: \"1%2F5+=+5%5E%28-1%29\" and \"125+=+5%5E3\". Subsituting these in we get:
\n" ); document.write( "\"%285%5E%28-1%29%29%5E%28t-2%29%29+=+5%5E3\"
\n" ); document.write( "On the left side the rule is to multiply exponents:
\n" ); document.write( "\"5%5E%28-t%2B2%29+=+5%5E3\"
\n" ); document.write( "Now the equation explicitly says each side is a power of 5. And if these two powers of 5 are equal, then the exponents must be equal!
\n" ); document.write( "\"-t+%2B+2+=+3\"
\n" ); document.write( "Solving this:
\n" ); document.write( "\"-t+=+1\"
\n" ); document.write( "\"t+=+-1\"
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