document.write( "Question 355205: PLEASE EXPLAIN HOW YOU GOT THE ANSWER\r
\n" ); document.write( "\n" ); document.write( "WRITE AN EQUATION FOR THE LINE THROUGH THE POINT (1,1) AND PERPENDICULAR TO THE LINE 2X+Y=9\r
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\n" ); document.write( "JOHN
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Algebra.Com's Answer #253770 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!
Hi,
\n" ); document.write( "*Note: parallel lines have the same slope. (they \"slant\" in the same direction so they do not cross one another: they are parallel)
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\n" ); document.write( "The slope intercept equation for a line is y = mx + b where m is the slope and y -intercept (the point where the line crosses the y axis)
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\n" ); document.write( "solving equation given for y, in order to find its slope
\n" ); document.write( " 2X+Y = 9 \r
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\n" ); document.write( "y = -2x + 9 Slope of this line is \"%28-2%29\" \r
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\n" ); document.write( "Our new line also with a slope of -2 (slope is negative, both lines slope to the left)
\n" ); document.write( "\"y+=+-2x+%2Bb\"
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\n" ); document.write( "substituting these values (1,1))to solve for b
\n" ); document.write( "\"+1+=+-2++%2Bb\"\r
\n" ); document.write( "\n" ); document.write( "\"+1+%2B+2+=+b\"
\n" ); document.write( "b = 3
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\n" ); document.write( "Equation of new line
\n" ); document.write( "\"y+=+-2x+++%2B+3\"\r
\n" ); document.write( "\n" ); document.write( "\"+graph%28+300%2C+300%2C+-10%2C+10%2C+-10%2C+10%2C+-2x+%2B+3%2C-2x+%2B+9%29+\"
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