document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=355180>Question 355180</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If the graph of y=x^2 is shifted down 3 units and Left 5 unites, then what is the equation of the new graph? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #253738 by </B><A HREF=/tutors/aboutme.mpl?userid=ewatrrr><B>ewatrrr(24785)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ewatrrr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ewatrrr><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=253738\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hi,<BR>\n" );
document.write( "*Note: y = x^2 with a  New vertex(-5, -3)<BR>\n" );
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document.write( "using the vertex form of the equation for a parabola <BR>\n" );
document.write( "y =(x -h)^2 + k where (h,k ) is the vertex<BR>\n" );
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document.write( "y = (x +5)^2 + -3\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+graph%28+300%2C+200%2C+-6%2C+5%2C+-10%2C+10%2C+x%5E2%2C%28x%2B5%29%5E2-3%29+ ALIGN=MIDDLE  ALT=\"+graph%28+300%2C+200%2C+-6%2C+5%2C+-10%2C+10%2C+x%5E2%2C%28x%2B5%29%5E2-3%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
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