document.write( "Question 355134: Is it possible for two containers with equal surface areas to be completely filled with different amounts of liquid? Explain. \n" ); document.write( "
Algebra.Com's Answer #253714 by Edwin McCravy(20060)\"\" \"About 
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document.write( "Yes indeed.  If you fill a flimsy paper cup completely full of water and then\r\n" );
document.write( "squeeze the sides of the cup making it oval shaped, what will happen?  It will\r\n" );
document.write( "overflow, right? Why?  You didn't change the surface area when you squeezed it,\r\n" );
document.write( "did you? No.  But the squeezed paper cup will not hold as much water as the\r\n" );
document.write( "unsqueezed one, yet the surface area of the squeezed cup is exactly the same as\r\n" );
document.write( "the surface area of the unsqueezed cup.  \r\n" );
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document.write( "Here is a better illustration.  Look at these two boxes:\r\n" );
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document.write( "BOX A and BOX B have the same surface area.  Here is why:\r\n" );
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document.write( "BOX A:\r\n" );
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document.write( "The front rectangle has area 3in x 6in or 18inČ\r\n" );
document.write( "The back rectangle also has area 3in x 6in or 18inČ\r\n" );
document.write( "The rectangle on the left has area 2in by 6in or 12inČ\r\n" );
document.write( "The rectangle on the right also has area 2in by 6in or 12inČ\r\n" );
document.write( "The bottom rectangle has area 3in by 2in or 6inČ\r\n" );
document.write( "The top rectangle also has area 3in by 2in or 6inČ\r\n" );
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document.write( "So the surface area of BOX A is \r\n" );
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document.write( "18inČ+18inČ+12inČ+12inČ+6inČ+6inČ = 72inČ\r\n" );
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document.write( "BOX B:\r\n" );
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document.write( "The front rectangle has area 2in x 8in or 16inČ\r\n" );
document.write( "The back rectangle also has area 2in x 8in or 16inČ\r\n" );
document.write( "The rectangle on the left also has area 2in by 8in or 16inČ\r\n" );
document.write( "The rectangle on the right also has area 2in by 8in or 16inČ\r\n" );
document.write( "The bottom rectangle (a square) has area 2in by 2in or 4inČ\r\n" );
document.write( "The top rectangle (also a square) also has area 2in by 2in or 4inČ\r\n" );
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document.write( "So the surface area of BOX B is \r\n" );
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document.write( "16inČ+16inČ+16inČ+16inČ+4inČ+4inČ = 72inČ \r\n" );
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document.write( "So the total surface area of both boxes is the same, 72inČ\r\n" );
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document.write( "However their volumes (how much they will hold) is different.\r\n" );
document.write( "Here is why:\r\n" );
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document.write( "The volume of BOX A is \r\n" );
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document.write( "V = LWH = 3in x 2in x 6in = 36inł \r\n" );
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document.write( "The volume of BOX B is \r\n" );
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document.write( "V = LWH = 2in x 2in x 8in = 32inł\r\n" );
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document.write( "So the two boxes have the exact same surface area but\r\n" );
document.write( "BOX A holds 4inł more than BOX B. \r\n" );
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document.write( "Edwin
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