document.write( "Question 355110: A corporation borrows $900,000 to expand its line of clothing. Some of the money is borrowed at 10%, some at 8% and at 9%. The annual interest payment to the lenders is $133,000. The amount borrowed at 8% is four times the amount borrowed at 10% . How much is borrowed at each rate ? \r
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document.write( "Can someone please help me solve this problem ?
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Algebra.Com's Answer #253640 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A corporation borrows $900,000 to expand its line of clothing. Some of the money is borrowed at 10%, some at 8% and at 9%. The annual interest payment to the lenders is $133,000. The amount borrowed at 8% is four times the amount borrowed at 10% . How much is borrowed at each rate ? \n" ); document.write( "-------------- \n" ); document.write( "Equations: \n" ); document.write( "Quantity Eq.::: x + y + z = 900,000 dollars \n" ); document.write( "Interest Eq.:::0.10x + 0.08y +0.09z = 133000 \n" ); document.write( "Quantity Eq.:::y = 4x \n" ); document.write( "--------------------------------- \n" ); document.write( "Substitute 4x for y: \n" ); document.write( "x + 4x + z = 900,000 \n" ); document.write( "0.10x + 0.08(4x) + 0.09z = 133000 \n" ); document.write( "----------------------------------------- \n" ); document.write( "Simplify: \n" ); document.write( "5x + z = 900,000 \n" ); document.write( "0.42x+0.09z = 133000 \n" ); document.write( "---- \n" ); document.write( "Multiply thru the 1st Eq. by 42. \n" ); document.write( "Multiply thru the 2nd Eq. by 500 \n" ); document.write( "----- \n" ); document.write( "210x + 42z = 42*900,000 \n" ); document.write( "210x + 45z = 500*133000 \n" ); document.write( "---------------------------------- \n" ); document.write( "Comment: Those equation conditions result \n" ); document.write( "in negative variable values. \n" ); document.write( "Please check the wording of your problem. \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |