document.write( "Question 355110: A corporation borrows $900,000 to expand its line of clothing. Some of the money is borrowed at 10%, some at 8% and at 9%. The annual interest payment to the lenders is $133,000. The amount borrowed at 8% is four times the amount borrowed at 10% . How much is borrowed at each rate ? \r
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\n" ); document.write( "\n" ); document.write( "Can someone please help me solve this problem ?
\n" ); document.write( "Thank you so much.
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Algebra.Com's Answer #253640 by stanbon(75887)\"\" \"About 
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A corporation borrows $900,000 to expand its line of clothing. Some of the money is borrowed at 10%, some at 8% and at 9%. The annual interest payment to the lenders is $133,000. The amount borrowed at 8% is four times the amount borrowed at 10% . How much is borrowed at each rate ?
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\n" ); document.write( "Equations:
\n" ); document.write( "Quantity Eq.::: x + y + z = 900,000 dollars
\n" ); document.write( "Interest Eq.:::0.10x + 0.08y +0.09z = 133000
\n" ); document.write( "Quantity Eq.:::y = 4x
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\n" ); document.write( "Substitute 4x for y:
\n" ); document.write( "x + 4x + z = 900,000
\n" ); document.write( "0.10x + 0.08(4x) + 0.09z = 133000
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\n" ); document.write( "Simplify:
\n" ); document.write( "5x + z = 900,000
\n" ); document.write( "0.42x+0.09z = 133000
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\n" ); document.write( "Multiply thru the 1st Eq. by 42.
\n" ); document.write( "Multiply thru the 2nd Eq. by 500
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\n" ); document.write( "210x + 42z = 42*900,000
\n" ); document.write( "210x + 45z = 500*133000
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\n" ); document.write( "Comment: Those equation conditions result
\n" ); document.write( "in negative variable values.
\n" ); document.write( "Please check the wording of your problem.
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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