document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=355097>Question 355097</A>: <I><SPAN STYLE=\"word-break: break-all;\"> What is the measure of an angle if the measure of its compliment is 10 degrees more than twice its measure? (Show your solution) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #253629 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=253629\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let the measure of angle be x<BR>\n" );
document.write( "thecomplement will be 90-x<BR>\n" );
document.write( "...<BR>\n" );
document.write( "90-x = 2x+10<BR>\n" );
document.write( "90-10=2x+x<BR>\n" );
document.write( "80 = 3x<BR>\n" );
document.write( "x= 80/3<BR>\n" );
document.write( "x= 26.6 deg<BR>\n" );
document.write( "the complement = 90-x= 63.4 deg<BR>\n" );
document.write( "...<BR>\n" );
document.write( "m.ananth@hotmail.ca </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );