document.write( "Question 355104: How many grams of 50% silver alloy and a 10% silver alloy must be mixed to obtain 24 grams of a 25% silver alloy? \n" ); document.write( "

Algebra.Com's Answer #253622 by robertb(5830) $\"\"$ $\"About$

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Let x = # of grams of 50% silver alloy
\n" ); document.write( "Then 24 - x = # of grams of 10% silver alloy.
\n" ); document.write( " $\"0.50x%2B0.10%2824+-+x%29+=+0.25%2A24\"$ ,
\n" ); document.write( " $\"0.50x%2B2.4+-+0.10x+=+6\"$
\n" ); document.write( " $\"0.40x+=+3.6\"$ ,
\n" ); document.write( " $\"x+=+9\"$ , and $\"24+-+x+=+24-9+=15\"$ .
\n" ); document.write( "Therefore he has to mix 9 grams of 50% silver alloy, and 15 grams of 10% silver alloy. \n" ); document.write( "

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