document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=39964>Question 39964</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Help with this one please!\r<BR>\n" );
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document.write( "sqrt2y+7 + 4 = y\r<BR>\n" );
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document.write( "I think I have to start by isolating the y to one side - is that right, and then do I subtract the 4 from both sides to cancel it out on the left?<BR>\n" );
document.write( "Please show me how to figure this!\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #25362 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=25362\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> sqrt(2y+7) + 4 = y<BR>\n" );
document.write( "sqrt(2y+7)=y-4<BR>\n" );
document.write( "Square both sides to get:<BR>\n" );
document.write( "2y+7=y^2-8y+16<BR>\n" );
document.write( "y^2-10y+9=0<BR>\n" );
document.write( "(y-9(y-1)=0<BR>\n" );
document.write( "y=9 or y=1<BR>\n" );
document.write( "Check the answers in the original equation.<BR>\n" );
document.write( "y=1 is extraneous.<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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