document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=355100>Question 355100</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A circle has a chord of length 10 cm. This chord is the perpendicular bisector of a radius of that circle. What is the area of the circle in square centimeters? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #253617 by </B><A HREF=/tutors/aboutme.mpl?userid=robertb><B>robertb(5830)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=robertb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=robertb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=253617\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The given chord perpendicularly bisects a radius of the circle, so we can form a right triangle where one leg measures 5 cm, the other leg measures <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=r%2F2 ALIGN=MIDDLE  ALT=\"r%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" >, and the hypotenuse measures r.  Then by the Pythagorean Theorem,<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=r%5E2+=+%28r%2F2%29%5E2+%2B5%5E2 ALIGN=MIDDLE  ALT=\"r%5E2+=+%28r%2F2%29%5E2+%2B5%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >,<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=r%5E2+=+r%5E2%2F4%2B25 ALIGN=MIDDLE  ALT=\"r%5E2+=+r%5E2%2F4%2B25\"   DISABLED_style= \"max-width:90%; height:auto;\" >,<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3r%5E2%2F4+=+25 ALIGN=MIDDLE  ALT=\"3r%5E2%2F4+=+25\"   DISABLED_style= \"max-width:90%; height:auto;\" >,<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=r%5E2+=+100%2F3 ALIGN=MIDDLE  ALT=\"r%5E2+=+100%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" >.<BR>\n" );
document.write( "Now the area of the circle is given by <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A+=+pi%2Ar%5E2 ALIGN=MIDDLE  ALT=\"A+=+pi%2Ar%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >.<BR>\n" );
document.write( "Substituting <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=r%5E2+=+100%2F3 ALIGN=MIDDLE  ALT=\"r%5E2+=+100%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" > into this area formula, we get<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A+=+100pi%2F3 ALIGN=MIDDLE  ALT=\"A+=+100pi%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" >square centimeters.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );