document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=355078>Question 355078</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two cyclists, 90 mi apart, start riding toward each other at the same time.  One cycles twice as fast as the other.  If they meet 2 h later, at what average speed is each cyclist traveling?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #253608 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=253608\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> distance 90 miles<BR>\n" );
document.write( "speed of one cyclist = x<BR>\n" );
document.write( "other speed = 2x<BR>\n" );
document.write( "time they drive =2 hours<BR>\n" );
document.write( "since they are travelling towards each other the effective speed = 2x+x=3x<BR>\n" );
document.write( "Time = distance /speed<BR>\n" );
document.write( "90/3x = 2<BR>\n" );
document.write( "6x = 90<BR>\n" );
document.write( "x = 15 mph speed of one cyclist.<BR>\n" );
document.write( "speed of other will be 2x = 2*15 = 30 mph.<BR>\n" );
document.write( "...<BR>\n" );
document.write( "m.ananth@hotmail.ca </SPAN>\n" );
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