document.write( "Question 354994: The length of a rectangle is 10 inches more than the width. the perimeter of the rectangle is 112 inches. Can you please help me find what the width of the rectangle is? \n" ); document.write( "
Algebra.Com's Answer #253606 by mananth(16946)![]() ![]() You can put this solution on YOUR website! let width be x \n" ); document.write( "length = x+10 \n" ); document.write( ".. \n" ); document.write( "Perimeter = 2*(L+W) \n" ); document.write( "2(x+x+10)=112 \n" ); document.write( "2(2x+10)=112 \n" ); document.write( "4x+20 = 112 \n" ); document.write( "4x=92 \n" ); document.write( "/4 \n" ); document.write( "x= 92/4 \n" ); document.write( "x 23 inches the width \n" ); document.write( "length = 23+10 = 33 inches. \n" ); document.write( "... \n" ); document.write( "CHECK \n" ); document.write( "33+33+23+23=112 \n" ); document.write( "... \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " |