document.write( "Question 354994: The length of a rectangle is 10 inches more than the width. the perimeter of the rectangle is 112 inches. Can you please help me find what the width of the rectangle is? \n" ); document.write( "
Algebra.Com's Answer #253606 by mananth(16946)\"\" \"About 
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let width be x
\n" ); document.write( "length = x+10
\n" ); document.write( "..
\n" ); document.write( "Perimeter = 2*(L+W)
\n" ); document.write( "2(x+x+10)=112
\n" ); document.write( "2(2x+10)=112
\n" ); document.write( "4x+20 = 112
\n" ); document.write( "4x=92
\n" ); document.write( "/4
\n" ); document.write( "x= 92/4
\n" ); document.write( "x 23 inches the width
\n" ); document.write( "length = 23+10 = 33 inches.
\n" ); document.write( "...
\n" ); document.write( "CHECK
\n" ); document.write( "33+33+23+23=112
\n" ); document.write( "...
\n" ); document.write( "m.ananth@hotmail.ca
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