document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=355016>Question 355016</A>: <I><SPAN STYLE=\"word-break: break-all;\"> one alloy contains 80% gold (in weight) and another alloy contains 55% gold. how many grams of each alloy should be contained to make a 40kg of an alloy that contains 70% gold? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #253605 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=253605\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 80% gold (in weight)  let this be x kg<BR>\n" );
document.write( "another alloy contains 55% gold. this will be 40-x kg<BR>\n" );
document.write( "Mix 40kg of an alloy that contains 70% gold?<BR>\n" );
document.write( "..<BR>\n" );
document.write( "80x+55(40-x)=40*70<BR>\n" );
document.write( "80x+2200-55x=2800<BR>\n" );
document.write( "25x=2800-2200<BR>\n" );
document.write( "25x=600<BR>\n" );
document.write( "x=600/25<BR>\n" );
document.write( "x= 24 kg ----- 80% gold<BR>\n" );
document.write( "balance 16 kgs will be 55% gold alloy<BR>\n" );
document.write( "...<BR>\n" );
document.write( "m.ananth@hotmail.ca </SPAN>\n" );
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