document.write( "Question 355064: The sum of the digit of a two digit number is 9. the ten digit number is 3 more than twice the one digit. \n" ); document.write( "
Algebra.Com's Answer #253604 by mananth(16946)\"\" \"About 
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let the number be xy
\n" ); document.write( "x+y =9
\n" ); document.write( "x=2y+3
\n" ); document.write( "plug value of x
\n" ); document.write( "in first equation
\n" ); document.write( "2y+3+y = 9
\n" ); document.write( "3y+3=9
\n" ); document.write( "3y=9-3
\n" ); document.write( "3y=6
\n" ); document.write( "y=2
\n" ); document.write( "...
\n" ); document.write( "x+y =9
\n" ); document.write( "y =2
\n" ); document.write( "so x = 7
\n" ); document.write( "number = 72
\n" ); document.write( "...
\n" ); document.write( "m.ananth@hotmail.ca
\n" ); document.write( "
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